Amanzi ebesetyenziswa ukupholisa nokufudumeza umoya kwiikhoyili zokutshintshiselana kobushushu zetyhubhu ezifinniweyo phantse ukususela ekuqaleni kokufudumeza kunye ne-air conditioner. Ukuqandisa ulwelo kunye nomonakalo obangelwa yikhoyili nakho bekusoloko kukho ixesha elifanayo. Yingxaki ecwangcisiweyo enokuthintelwa amaxesha amaninzi.
Kweli nqaku, sidwelise iingcebiso ezimbalwa ezinokukunceda uthintele i-crack coil eqandisiweyo ebusika.
1. Ukuba iyunithi ayisebenzi ebusika, onke amanzi akwinkqubo kufuneka akhululwe ukuze kuthintelwe ukuqhekeka kwekhoyili.
2. Kwimeko engxamisekileyo efana nokucinywa kombane okanye ukulungiswa kombane, i-air damper kufuneka ivalwe ngoko nangoko ukuqinisekisa ukuba akukho moya wangaphandle ongena kwinkqubo. Ulwelo aluphonswa kwikhoyili kwaye ubushushu obuphantsi ngaphakathi kwe-AHU bunokubangela ukwakheka komkhenkce. Ubushushu ngaphakathi kwe-AHU kufuneka buhlale bungaphezulu kwe-5 ℃.
3. Ukucoca i-Coil kunye nesihluzo samanzi rhoqo. Izinto ezibambeke kwipayipi zibangela ukujikeleza kwamanzi okungalunganga. Umgibe wolwelo kwityhubhu ye-coil obangela umonakalo we-coil xa kukho imeko yokukhenkceza.
4. Uyilo olungalunganga lwenkqubo yolawulo. Ezinye iinkqubo zolawulo zilungisa kuphela ukuvulwa kwevalvu yamanzi kungekhona isantya sefeni ngokusekelwe kulawulo lobushushu bangaphakathi. Ukungabikho kolawulo lwefeni okubangela ukujikeleza kwamanzi okubuthathaka kunye nomthamo womoya ophezulu, okubangela amanzi aqandisiweyo kwikhoyili. (Isantya samanzi esiqhelekileyo kwikhoyili kufuneka silawulwe kwi-0.6 ~ 1.6m/s)
Ukujikeleza kwekhoyili apho uxinzelelo lwakha khona, kunye nendawo ebuthathaka kuloo mjikelezo. Uvavanyo olubanzi lubonise ukuba ukungaphumeleli kuya kubonakala njengendawo evuvukileyo kwi-tube header okanye i-bend eyandayo. Kwiimeko ezininzi, yindawo eya kuqhambuka.
Nceda ujonge ngezantsi ukuze ufumane ubalo loxinzelelo olubangelwa yi-coil eqandisiweyo.
P=ε×E Kg/cm2
ε = Umthamo Onyukayo (Imeko: 1 uxinzelelo lomoya, 0℃,umthamo wamanzi oyi-1 kg)
ε = 1÷0.9167＝1.0909 (9% Ukwanda kwevolumu)
E= imodulus yokuthamba xa uxinezelekile (Ice = 2800 Kg/cm2)
P=ε×E=(1.0909-1)×2800=254.5 Kg/cm2
Uxinzelelo olubi lubangela umonakalo kwi-coil. Umonakalo kwi-coil ngenxa ye-liquid line freeze unxulumene noxinzelelo olukhulu oluveliswa ngexesha lokwenziwa komkhenkce. Indawo equlathe lo mkhenkce inokusingatha kuphela olu xinzelelo longezelelweyo de lufikelele kumda obangela umonakalo kwi-heat exchanger kunye nokungaphumeleli okulandelayo.
Ukuba unemibuzo malunga neyunithi yokuphatha umoya ebusika, nxibelelana ne-Airwoods namhlanje! Sikhokela ababoneleli behlabathi beemveliso ezintsha ze-HVAC kwaye sakha isisombululo somgangatho womoya kwiimarike zorhwebo nezoshishino. Ukuzinikela kwethu kukubonelela abathengi bethu ngeemveliso kunye neenkonzo ezilungileyo ngexabiso elifikelelekayo kunye nokudala imeko-bume yokuhlala engcono.
Ixesha lokuposa: Jan-13-2021
